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Question

For the aqueous reaction

dihydroxyacetone phosphate↽−−⇀glyceraldehyde−3−phosphate

the standard change in Gibbs free energy is  Δ𝐺°′=7.53 kJ/mol .

 Calculate  Δ𝐺  for this reaction at  298 K  when  [dihydroxyacetone phosphate]=0.100 M  and  [glyceraldehyde-3-phosphate]=0.00400 M .

Answer 1

You would use the formula ΔG= ΔG^°'+RTlnQ, where R is the gas constant (8.314 J/molK) and T is absolute temperature (in Kelvin) and Q is the reaction quotient, Q=[reactants]/[products]. You're given Δ𝐺°′=7.53 kJ/mol. From there, you just plug and solve for Δ𝐺.