Find the measure of each angle in Triangle ABC. m∠a=(50−x)°m∠b=(9x−40)°m∠c=90

Answer 1

Since m is / C = 90, A + B = 90, so the three angles have a sum of 180.

So, (50 - x) +(9x - 40) = 90

8x + 10 = 90

8x = 80

x = 10

/ A = 50 - 10 = 40

/ B = 9(10) - 40 = 50

Answer 2

The 3 angles in a triangle ALWAYS add up to 180° so:

(50 - x) + (9x - 40) + 90 = 180

(50 - 40 + 90) + (-x + 9x) = 180

100 + 8x = 180

8x = 80

x = 80/8 = 10

So, angle A = 50 - 10 (or 40°)

Angle B = 9(10) - 40 = 50°

and Angle C was given to us as 90°