Mike D. answered 07/21/20
Experienced high school discrete math teacher
Well the training track will have two straight parts (the length of the rectangle), and two semi circular parts (circle radius 71/2 because 71 is the width of the rectangle).
A circle has circumference 2πr where r is the radius and π=3.14 (can also assume 22/7).
So a semi circle has length half the circumference = πr
So the track length will be 96 + 96 + πr + πr (where r= 71/2 = 35.5, and π=3.14).
That works out as : 414.9 m. (training tracks are usually approx 400m so this makes sense).