The perimeter of a rectangle is 128 inches. Find the dimensions of the rectangle if 12 the length increased by 22, is 9 less than three times the width.

Answer 1

P = 2l + 2w

P = 128 inches, l = x + 22, and w = 3x - 9

2(x + 22) + 2(3x - 9) = 128

2x + 44 + 6x - 18 = 128

8x + 26 = 128

8x = 94

x = 11.75

The length is 11.75 + 22 = 33.75 inches. The width is 3(11.75) - 9 = 26.25 inches.