
Sam Z. answered 07/16/20
Math/Science Tutor
h(x)=2x−3 ; j(x)=−4x+6 ; k(x)=−2x+3
h(x)+j(x)=()+()=
2x-3-4x+6=-2x+3 correct.
Stephanie T.
asked 07/16/20Algebraically show that each of the given combinations are equivalent to the given functions. h(x)+j(x) is equivalent to k(x) given:h(x)=2x−3 ; j(x)=−4x+6 ; k(x)=−2x+3
h(x)+j(x)=()+()=
)=
Sam Z. answered 07/16/20
Math/Science Tutor
h(x)=2x−3 ; j(x)=−4x+6 ; k(x)=−2x+3
h(x)+j(x)=()+()=
2x-3-4x+6=-2x+3 correct.
It really is that simple.
h(x) + j(x) = (2x - 3) + (-4x + 6) = 2x - 3 - 4x + 6 = -2x + 3 = k(x)
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