5. NEED HELP FAST!!!

Question

The reaction

C4H8(g)⟶2C2H4(g)

has an activation energy of  262 kJ/mol.  At  600.0 K,  the rate constant,  𝑘,  is  6.1×10−8 s−1.  

What is the value of the rate constant at  790.0 K?

Answer 1

There's a formula you can use to solve this which is as follows...

ln k₂ = ln k₁ - (E_a/R)(1/T₂-1/T₁)

Now you can just plug in your known values and solve for your unknown

ln k₂ = ln 6.1E-8 - (262000/R)(1/790-1/600) [NOTE: The activation energy in the equation is in J/mol]

When you solve for k₂ you get that its 0.019

Plug the right side into a calculator, then take e^(ans)