Alex M.

asked • 07/14/20

Proving delta epsilon limits at infinity for unknown function

I have a question and it's limx>inf (f(x)= 2 and I have to prove that N exists and if x>N 1<f(x)<3


I started trying to set up my proof with |f(x)-2|<E but I've never done a problem like this with an unknown function and I have no idea what to do next. If anyone can help solve this or let me know where to start, it would be greatly appreciated!

Stanton D.

Hi Alex M., It would appear that you are about there. The idea of lim x->.infinity. implies exists n such that |f(x)-2|< epsilon. Therefore, setting epsilon to 1 is just a special instance of that. That doesn't GIVE you the least possible N, of course, since you don't have the function specified! -- Cheers, --Mr. d.
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07/14/20

1 Expert Answer

By:

Sava D.

tutor
Note, the number N does not have to be the least, we simply know N exists, by the definition of limit.
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07/14/20

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