If this is a simple interest problem and x = the amount in the 9% account and 3000-x is the amount in the 12% account, then
.09x + .12(3000-x) = 330
You find that
x = $1000
3000 - x = $2000
Ana C.
asked 07/13/20Todd invests $3000 in two different accounts. The first account paid 9 %, the second account paid 12 % in interest. At the end of the first year he had earned $330 in interest. How much was in each account?
$ at 9 %
$ at 12 %
If this is a simple interest problem and x = the amount in the 9% account and 3000-x is the amount in the 12% account, then
.09x + .12(3000-x) = 330
You find that
x = $1000
3000 - x = $2000
Get a free answer to a quick problem.
Most questions answered within 4 hours.
Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.