Andrea W.

asked • 07/13/20

NEED HELP FAST!!!

The reaction


C4H8(g)⟶2C2H4(g)

has an activation energy of  262 kJ/mol.  At  600.0 K,  the rate constant,  𝑘,  is  6.1×10−8 s−1.  What is the value of the rate constant at  790.0 K?

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Karina S. answered • 07/13/20

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Use the Arrhenius equation!

k=A x e-Ea/RT


  1. I plugged in the given rate, activation energy, R=8.31, and T=600 to find A (frequency factor) A=19.03
  2. I then used A to find k at 790K.
  3. k=18.28599757
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J.R. S.

tutor
Don't see your calculations but your k is significantly different from the original k at 660K so doesn't seem correct. Did you remember to convert R to units of kJ/Kmol or to change Ea to J/mole, so that the units of R and Ea agree?
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07/14/20

Julie S.

I didn't do the calculations myself, but it doesn't look right to me either...
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07/18/20

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