NEED HELP FAST!!!

Question

Consider the given reaction.

A(aq)+B(s)↽−−⇀C(aq)𝐾=9.40

Suppose  13.7 mol A  reacts with excess  B  in  5.90 L  of solution. Calculate the concentration of  C  at equilibrium.

Answer 1

You set up the equilibrium calculation as follows: K=[C[/[A]. Bis a solid and does not participate in the equilibrium reaction. You express the concentration is M (moles/L) so 13.7/5.90=2.32 M , the concentration of A. Set up an ICE table as follows:

[A] [C]

initial 2.32 M ---

change -x +x

equilibrium 2.32-x x

So, 9.40= x/2.32-x, solve for x, x=2.10. At equilibrium [C]=2.10 M. To check put in the equilibrium concentrations and you should get a number close to 9.4.. K=2.10/(2.32-2.10)=9.54, close considering rounding off of results.