the vertex of this parabola is at (-2,-3). When the x. value is -1and the y value is -5, what is the coefficient of the squared expression. in. the parabolas equation

Answer 1

Vertex form of a parabola: y = a(x - h)² + k, where (h, k) is the vertex of the parabola.

Plug in the vertex to get y = a(x + 2)² - 3. (The -2 got negated because of -h)

Plug in the point (-1,-5) to get -5 = a(-1+2)² -3 (This could be have been done in the previous step)

Now let's solve for a:

-5 = a(1)²-3

-5 = a-3

-2 = a

Since y=ax²+bx+c is the standard form of a parabola and is another way to write y=a(x-h)² +k, the coefficient of the squared term is "a", so -2 is your answer.

Answer 2

y = a(x - h)² + k vertex form

y = a(x + 2)² - 3 given vertex

-5 = a(-5) + 2)² - 3 given point

-5 = a(-3)² - 3

Can you complete and answer?