
Karen A. answered 07/08/20
Patient Math Tutor. Taught probability & Calc at University
Jon could be right, but it seems to me like this might be a badly worded trick question.
you are going to toss 3 coins . Since the two girls Are selecting outcomes that Can NOT both occur, then the probability of tiffany being right And Emily being right is zero.
Or maybe you are supposed to think about both and notice that T and E are dependent (not independent) since you can’t just multiply the probabilities to get the probability of T and E
T= Tiffany Right
E=Emily Right
P(T and E) = 0
P(T) *P(E) = .5*.5 = .25.
.25 is Not the same as P(T and E) because if one Is right it changes the probability that the other is right.