No, you need to integrate xe-12x from 1 to ∞ and if this integral converges then the series converges. In this case the integral has a factor of e-12x goes to 0 for large x and is bounded at x=1; therefore, the integral and the series converge.
Angie A.
asked 07/02/20Please help me with this Calculus 2 series question I am stuck on
Use the Integral Test to determine whether the series is convergent or divergent.
| ∞ | |
ne−12n
| |
| n = 1 |
ok so I know this is an integral test
i know i have to take the derative
and I got -12e^-12x+e^-12x, however I do not know what to do next
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