Kimberly S.
asked • 06/27/20Find a formula for the inverse of the given function. f(x) = k3x k2x + 1 with k ≠ 0
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2 Answers By Expert Tutors
I am guessing that f(x) = k3x / (k2x + 1)
If so, let y = k3x / (k2x + 1)
Switch x and y: x = k3y / (k2y + 1)
Solve for y: xk2y + x = k3y
xk2y - k3y = -x
y(xk2 - k3) = -x
y = x / (k3 - xk2) = f-1(x)
Sam Z. answered • 06/27/20
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(12)
Math/Science Tutor
fx=5kx+1....................................
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William W.
Kimberly, can you clarify what f(x) is? Is this k*3x? If so. what is the operation between "k3x" and "k2x". Could this perhaps be k3x^2 + k2x + 1?06/27/20