A rectangular bedroom is 3 ft longer than it is wide. Its area is 130 ft2. What is the width of the room?

Answer 1

Area= length x width (A=lw)

130=A=lw

130= (w+3)(w)

130=w^2 +3w

0= w^2 +3w - 130

0=(w+13)(w-10)

w= -13 or +10

Since width cannot be negative, the width equals 10 and we know that length is equal to the width +3, so the length equals 13.

Lets double check, 10*13 = 130, and 13 is 3 more than 10. The width is 10.

Answer 2

Hello Sarim,

Let the width of the rectangular room be 'w'

Length of the rectangular room is 'w+3'

Area of the rectangular room is 130 sq ft

According to question,

Area of the rectangular room = length * width

130 = (w+3)*w

130 = w^2 + 3w

-130 + 130 = w^2 +3w - 130 (Subtracting by 130 on both sides)

0 = w^2 +3w - 130

0 = (w+13)(w-10) (by factorizing)

w = -13 or +10

Since width cannot be negative, so width of the rectangular room, w = 10 ft

As we know, Length of the rectangular room is 'w+3',

Therefore Length = 10 + 3 = 13 ft

Happy to help :)