
Adela D. answered 06/24/20
Current PhD Student in Applied Math with Tutoring Experience
Hi Joanna! Great question: your explanation of the quadratic function and argument for why it is a good model of falling objects is solid. Let's answer your question.
You ask about why we use a quadratic function instead of a linear function. You are spot-on when you note that as objects fall, they pick up speed. A linear function would imply that the object falls at a constant rate at all times, which is not the behavior we want. A quadratic function is one way to model a change in speed, or acceleration. There are also interesting reasons from physics that support the idea that quadratic models are good at describing motion under gravity!
Now on to solving: you want to find the time t at which the pinecone hits the ground, after falling from an initial height of 20 feet. We can do this by solving for when H(t) = 0, using our equation for H(t):
H(t) = 0 = -16 t^2 + 20
There are lots of ways to solve a quadratic equation. Here, we can move (-16t^2) to the other side to get
16t^2 = 20
now we can divide by 16 and reduce our fraction to get
t^2 = 20/16 = 5/4
and now we can take the square root to find
t = square root (5)/square root(4) = square root(5)/2 which is approximately 1.12. This tells us that 1.12 seconds after being released, the pinecone will hit the ground.
Note that there is a second solution: t= -1.12 also satisfies t^2 = 5/4. In order to decide which solution is appropriate, we need to look at our application. We're interested in finding the number of seconds after which a pinecone will hit the ground. A negative number of seconds would mean that the pinecone hits the ground before it's been released: clearly that answer doesn't fit our application, so we can discard it.
A more general way to solve quadratic equations involves a formula for the solution, which you may have heard of:
To solve the equation ax^2 + bx + c = 0, we use the formula
x = -(b) +/- square root (b^2 - 4 ac)
This formula lets us find values of x that make the equation equal to 0.