If we have 4.57 mol of carbon dioxide gas at a temperature of 386 K and volume of 4821 mL, what is the pressure inside this vessel?

Answer 1

Let us use the PV=nRT formulae

From the above equation, we can substitute every letter with its value except P

P * 4.821 L = 4.57 mol * 8.314 * 386 K

P = ( 4.57 mol * 8.314 * 386 K)/4.821 L

Finally :

P = 3,041 atm

Answer 2

Use the Ideal Gas Law equation: PV = nRT

P = pressure = ?

V = volume in liters = 4.821 L

n = moles = 4.57 moles

R = gas constant = 0.0821 Latm/Kmol

T = temperature in Kelvin = 386 K

Solving for P we have...

P = nRT/V

P = (4.57)(0.0821)(386) / 4.821

P = 30.0 atm (to 3 significant figures)