Need some help with this question improper integral question

Question

49
dx/49-x
0

Answer 1

You want to make this into an integral that you can find by using u-substitution.

u = 49-x

du = -dx

-∫ dx/√u = -∫ u^-1/2du

-2[u^1/2] from [0, 49]

-2[(49-x)^1/2] from [0, 49]

-2[0 - (49)^1/2]

= 14