answer the question as true or false

Question

The function  is not integrable on   

Answer 1

you split the integral over the discontinuity

integral [x^2] , x= [-1,0)

+ integral [x+1], x = (0,1)

(1/3) x^3 on [-1,0) + (x^2 + x) on (0,1]

[ 0 - (-1/3)] + [ (1+1) - 0]

1/3 + 2 =

7/3