
Rosemarie N. answered 06/15/20
Experienced SAT/ACT Prep and Tutoring
Let's set a = adult tickets and c = child tickets.
That would make:
11a + 2c = 151
11a + 10c = 271
There are two ways of solving this:
- Set the equations equal to each other. Notice how both equations have 11a in them. To make it easy, let's set each equation equal to 11a. We get 11a = 151 - 2c and 11a = 271 - 10c.
- Since 11a is equal to 11a, set 151 - 2c = 271 - 10c
- Now solve for c.
- 8c = 120
- c = 15
- Plug c back into one of the equations to find a.
- 11a + 2(15) = 151
- 11a + 30 = 151
- 11a = 121
- a = 11
- Since both times the school sold 11 adult tickets, the only difference is 8 child tickets and $120. Therefore 8c = 120.
- c = 15
- Plug c back in to find a
- 11a + 10(15) = 271
- 11a + 150 = 271
- 11a = 121
- a = 11
The answer is A. Each adult ticket costs $11, and each child ticket costs $15.