Mark M. answered 06/10/20
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Retired math prof. Calc 1, 2 and AP Calculus tutoring experience.
Let u = 4x + 5. Then du = 4dx and x = (u-5)/4.
So, the integral can be rewritten as (1/4)∫u14(u - 5)(1/4)du = (1/16)∫[u15 - 5u14]du =
(1/256)u16 - (5/240)u15 + C = (1/256)(4x+5)16 - (1/48)(4x+5)15 + C