Patrick B. answered • 06/10/20
Tutor
4.7
(31)
Math and computer tutor/teacher
No, this integral involves special functions...
Perhaps you meant: arctan(x) / (1 + x^2)
Then U = arctanx
dU = dx/(1+x^2)
the integral then becomes: U du
which integrates to (1/2)U^2
(1/2)(arctanx)^2
plug in your limits and you're set to go
