math help please asap!!!!!!!!!!

Question

1. A survey of the freshman class at PAW was given and the results are shown below. Complete the table and answer the given prompts.

	Speak a Second	Language	Do not Speak a	Second Language	Totals
Class Average	90	70	15
Class Average Not	90	10	50
Totals

a. How many freshmen students were surveyed?

b. What percentage of the freshmen students speak a second language and have a class average of at least 90? (show work, example 5/20 = 25% , round answer to the nearest percent )

c. What percentage of the freshmen students with a class average of at least 90 do not speak a second language? ((show work, example 5/20 = 25% , round answer to the nearest percent )

d. How many of the freshmen students do not speak a second language?

Answer 1

A. There are 145 freshmen surveyed.

B. P(Speak a 2^nd Language) = 80/145

P(Class Average ≥ 90) = 85/145

P(Speak a 2^nd Language ∩ Class Average ≥ 90) = (80/145)*(85/145) = 0.3234

About 32% of freshmen speak a second language and have a class average of at least 90.

C. P(Don't Speak a 2^nd Language|Class Average ≥ 90) = (15/85)÷(85/145) = 0.3010

About 30% of freshmen with a class average of at least 90 don't speak a second language.

D. 65 freshmen don't speak a second language.