Separate 846 into three parts so that the second part is twice the first part and the third part is triple the second part word equations could be used to solve the problem

Answer 1

So we need to break 846 in 3 parts (I assume those parts ADD to 846).

Let's call part 1 "x"

Call part 2 "y"

and part 3 "z".

Well, the idea was that x + y + z = 846.

It also says that: "the second part is twice the third part." So y = 2x

Finally, it says that: "the third part is triple the second part." So z = 3y

Now let's go back to our original equation x + y + z = 846.

Let's plug in values for y and z: x + 2x + 3y = 846 ---> x + 2x + 3(2x) = 846

---> x+ 2x + 6x = 846.

Now just solve for x, and plug it back in to find y and z.

I hope this helps!!

Best,

Sam

Answer 2

x + 2x + 3(2x) = 846

Can you solve for x and answer?