For a confidence interval for a mean, we need four things. Luckily, the problem explicitly gives us 3 of the 4 things. Those four things are:
- Sample mean (xbar)
- Sample Standard Deviation (s)
- Sample Size (n)
- Normal quantile associated with our desired confidence level (z)
Here's what we've been given:
- xbar = 17
- s = 3.9
- n = 189
- confidence level = 95%, i.e. alpha = 0.05. These are equivalent statements. To get z, we can look it up in a standard normal quantile table, such as this one http://cs.ru.nl/~tomh/onderwijs/dm/dm_files/normtable.pdf.
In tables like this, the numbers in the middle are probabilities (area under the curve), and the numbers on the left and top are associated with standard normal quantiles (a.k.a "z-scores"). When constructing a confidence interval, we want the area under the curve to be equal to our confidence level, which means we want half of alpha on each tail end. So to get our z-score, we look up the z-score associated with an area of alpha/2 in the right tail.
alpha/2 = 0.025. Since there is 0.025 to the right of our z-score, that means there is 0.975 to the left of our z-score. So we look in the table and find where it says "0.975" or as close to that as possible, somewhere in the numbers in the middle. We find it, and all the way to the left it says "1.9", and all the way at the top it says "0.06," so our z-score is 1.96.
Now we have everything we need to construct our confidence interval. It will simply be:
xbar ± z * s/√n
we plug in everything we know and we get:
17 ± 1.96 * 3.9/√189
17 - 1.96 * 3.9/√189 ≈ 16.444
17 + 1.96 * 3.9/√189 ≈ 17.556
So our 95% confidence interval is (16.444, 17.556)