What is the slope of a line perpendicular to the line whose equation is 4x - 3y = -27? Fully reduce your answer. Show all wo

Answer 1

First convert the original equation into y = form to find the slope.

Subtract 4x on both sides leaving -3y = -27 - 4x

This leaves y = (-27 - 4x)/(-3)

You can divide both -27 and -4x by -3 individually to get 9 and 4/3 respectively

This makes your equation y = 9 + (4/3)x

Whenever an equation is in y = mx + b form, the 'm' represents the slope. In this case the slope is 4/3.

So a line perpendicular to this equation would be any line with a slope of -3/4 (the negative reciprocal of the slope)