
Mark M. answered 05/26/20
Mathematics Teacher - NCLB Highly Qualified
y = abx
5 = ab0
5 = a
y = 5bx
10 = 5b1
2 = b
y = 5(2)x
Katelyn H.
asked 05/26/20x. y
0. 5
1. 10
2. 20
3. 30
Mark M. answered 05/26/20
Mathematics Teacher - NCLB Highly Qualified
y = abx
5 = ab0
5 = a
y = 5bx
10 = 5b1
2 = b
y = 5(2)x
Mark: When x = 3, your equation, y = 5(2)^x does not follow the given data.
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