
PETE C. answered 05/20/20
SAT MATH
Line P passes through POINTS (-2,6) and (4,-3).
Using y=mx + b where m is the SLOPE(rise divided by the run), and b is the Y-INTERCEPT.
First, determine the SLOPE. RISE/RUN = (6 - (-3))/(-2 -4) = (6+3)/(-6) = 9/-6 = - (3/2)
Pick the POINT (4,-3) and plug into the Y-INTERCEPT EQUATION above to determine the Y-INTERCEPT.
y = mx + b
-3 = (-3/2)(4) + b
-3 = -12/2 + b
-3 = -6 + b
6-3 = b Adding 6 to both sides.
b = 3 The Y-INTERCEPT is 3. The line crosses the Y-AXIS at 3 when X is zero. (0,3)
Now, we have our equation of the line P;
Y = (-3/2)X + 3
Hope this was helpful Natarsha.