A total of 936 people attended the play admission was $2.00 for adults and 0.75 for students the total ticket sales amounted to 1,109. How many students and adults attended the school play?

Question

A total of 936 people attended the play admission was $2.00 for adults and 0.75 for students the total ticket sales amounted to 1,109. How many students and adults attended the school play?

Answer 1

Hi,

I did the same setup as David. My compliments to David and got the same answers. Did it a multiple of times even walking away and revisiting it. Is there an error in the numbers as was previously asked?

Answer 2

1.Write a system of equations

X=adult tickets bought

y=student tickets bought

x+y=936 ---isolate y---> y= 936-x

2x+.75y=1109

2.After Isolating y in the first equation, solve for x with substitution method.

2x+.75(936-x)=1109

2x+702-.75x=1109

1.25x+702=1109

1.25x=407

x=325.6 cannot have .6 of a person, so 326

3.Solve for y with substitution method

2(326)+.75y=1109

652+.75y=1109

.75y=457

y=609.3 =610

or

326+y=936

y=610

326 adults and 610 students attended the play.

Answer 3

We have 2 unknowns, so we need 2 equations to solve it The unknowns are the # of students and # of adults.

Let x= # of adults

y= # of students

Eq. 1 x + y = 936----->x = 936 - y

Eq. 2 2x + .75y = 1109

Using the value of x from Eq. 1 in Eq. 2 we can solve for y:

2(936 - y) + .75y = 1109

1872 - 2y + .75y = 1109

1872 - 1.25y = 1109

1872 - 1109 = 1.25y

763 = 1.25y

y = 610.4

Using this value in Eq. 1 we can solve for x:

x = 936 - y

x = 936 - 610.4

x = 325.6

These answers work out, but do not make sense since you cannot have "partial" people. Is the problem correct, or was there a mistake in copying it down?

Hope this helps!