A ball is thrown from an initial height of 6 feet with an initial upward velocity of 29 ft/s. The balls height h in feet after t seconds is given by the following. h=6+29t-16t^2

Question

Find all values of t for which the balls height is 18 feet.

Answer 1

6 + 29t - 16t^2 = 18

16t^2 - 29t + 12 = 0

t = (29 +- √(29^2 - 4*12*16))/32

t = (29 +- √73)/32

t = 0.639249882958827, 1.17325011704117