Algebra 1. Quadratic Functions, Pls help

Question

Identify the Vertex, axis of symmetry and the y-intercept of the following equation.

Equation: y=(x-3)^2 (^2 stands for exponent)

A=____

H=____

K=___

Vertex= (_,_)

Vertex = min or max?

Axis of symmetry: x=___

Y-intercept= (0,_)

Answer 1

f (x) = a(x-h)² + k, where (h, k) is the vertex of the parabola.

y=(x-3)²

A=1 (There is nothing there. Where there is nothing there, there is a 1. Kind of like x = 1x, but the 1 is not shown)

H=3

K=0

Vertex= (3,0)

Vertex = min or max? This is determined by the sign of the a term. It is positive in this case. So the parabola opens up and the vertex is a min

Axis of symmetry: x=3 This comes from the x coordinate of the vertex

Y-intercept= (0,9)

Plug in x=0 and solve

y=(0-3)² = (-3)² = 9