
Patrick B. answered 05/12/20
Math and computer tutor/teacher
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the x be an element of the set defined by the left side of the equality
then x is in A or B but not both
so if x is in A, then x is not in B. That means x is in A-B
but if x is in B, then x is not in A. That means s is in B-A
so x is either in A-B or B-a which proves the statement --->
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Let y be an element of the set defined by the right side of the equality
then x is A but not B or x is in B but not A.
that means x cannot be in both A and B at the same time,
so x is NOT an element of the intersection.
since x is in A or B (but not both) we have
x in the union but not the intersection, which
proves the statement <-----
the sequence does not converge to 11