Find the value for x to the nearest tenth.

Question

1. I got stuck on How to solve this problem and how to set it up

A. 6.4

B. 5.2

C. 5.8

D. 6.2

Answer 1

if you put 2 radiuses to the ends of chord x you get right triangle (45° + 45° = 90°) with legs 9 and hipotenuse

2x = 9·sqrt(2). From here x = 9sqrt(2)/2 ≈ 6.36 ≈ 6.4

Answer: x = 6.4