Nestor R. answered 05/09/20
Statistician with a very good grounding in Algebra
h = -16t2 + 24t + 30
At time t=0, h=30
At time t=1, h= -16(12) + 24(1) +30 = -16+24+30 = 38
At time t=2, h= -16(22) + 24(2) + 30 = -16*4 + 48 + 30 = 14
At time t=3, h= -16(32) + 24(3) + 30 = -16*9 + 72 + 30 = -144+102 = -42. <== clearly too far
So the book reaches the ground at a time between t=2 and t=3.
Let a = -16, b=24 and c=30
By the quadratic formula, h=0 when t = [-b +/- sqrt(b2 - 4ac)] / 2a
Plugging values of a, b and c into the formula, t = [-24 +/- sqrt(2496) / -32
t = (-24+49.96) / -32 = -0.81 (not possible), OR
t = (-24-49.96) / -32 = 2.31 which is the correct answer. Note, as shown above, t is between 2 and 3.