
Douglas B. answered 05/09/20
Tutor
4.9
(83)
Precalculus tutor with masters degree in applied math
We apply Leibniz' integral rule:
F'(x) = sin(2^4)*d/dx(2) - sin((x^3)^4)*d/dx(x^3)
= sin(2^4)*0 - sin(x^12)*3x^2
= -3x^2sin(x^12).