Inactive Tutor answered 05/09/20
Tutor
New to Wyzant
We apply Leibniz' integral rule:
F'(x) = sin(2^4)*d/dx(2) - sin((x^3)^4)*d/dx(x^3)
= sin(2^4)*0 - sin(x^12)*3x^2
= -3x^2sin(x^12).
David S.
asked 05/08/20Find F ′(x) for
.
Options:
| 1) | sin(24) - sin(x12) |
| 2) | sin(x7) |
| 3) | -sin(x12) |
| 4) | -3x2sin(x12) |
Inactive Tutor answered 05/09/20
We apply Leibniz' integral rule:
F'(x) = sin(2^4)*d/dx(2) - sin((x^3)^4)*d/dx(x^3)
= sin(2^4)*0 - sin(x^12)*3x^2
= -3x^2sin(x^12).
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