Which are approximate solutions of the quadratic equation x2+2x-48=0

Answer 1

x^2 + 2x -48 = 0 need 2 numbers which multiple to -48 and add to +2 those are +8 and -6

(x+8)(x-6) = 0

x+8 =0 x=-8 x-6 = 0 x=6

Solutions are x=6 and x=-8