A rectangle has a perimeter of 72 inches. The length is 3 inches more than twice the width. What is the length of the rectangle in inches? 11 22 25 36

Answer 1

If x= the width of the rectangle, then the length = 2x + 3. Since the perimeter is 72 inches, and we know that a rectangle has two sides equal to the width and 2 sides equal to the length, we would construct the following equation:

2x + 2(2x +3) = 72

2x + 4x + 6 = 72

6x = 66

x = 11

Since the width of the rectangle (x) is 11 inches, the corresponding length would be 2x + 3 = 2(11) + 3 = 25. Therefore, the length of the rectangle is 25 inches.

Answer 2

L = 2w +3

p = 2w + 2L

p = 72 inches

p = 2w + 2(2w+3)

p = 2w + 4w +6

72 - 6 = 6w

66 = 6w

w = 11 inches

L = 2w +3

L = 2(11 inches) + 3

L = 22 +3 inches

L = 25 inches

Answer 3

Let x = width

2x+3 = length

Perimeter = length + length + width + width Plugging in values

72 = 2x+3 + 2x+3 + x + x Now this can be solved. Combine like terms

72 = 6x + 6 Subtract 6 from both sides

66 = 6x Divide both sides by 6

11 = x This is the width, the problem is asking for the length

length = 2x + 3

length = 2(11) + 3

length = 25 inches