Raymond B. answered 05/06/20
Math, microeconomics or criminal justice
P(M)=.48
P(P) = .42
P(M^P) = .38
P(P/M)=P(P) if independent events,
P(M/P) = P(M) if independent
they are dependent if the occurrence of one event changes the probability of the other event
Bayes Theorem is an identity, always true,
P(M/P)P(P) = P(P/M)P(M)
or P(M/P) = P(P/M)P(M)/P(P)
but if they are independent, the Bayes Theorem "collapses to
P(M)P(P) = P(P)P(M), which is a more obvious identity, always true
P(M^P) = P(M)P(P) if they are independent events
If P(M)= .48 and P(P) = .42
then P(M^P) = (.48)(.42) = .2016
IF .P(M^P) = .38 the events are dependent since .38 does not equal .2016
If one event occurs, that increases the probability of the other event, making them dependent events
P(M)=.48=P(A)
P(P)=.42=P(B)
P(A/B) = .79
P(A/B)P(B)= .79(.42)=.3318
P(B/A) = .9
P(B/A)P(A)=.9(.48)= .432 = about .42 as in answer D) so C) is the best answer,
although none are fully accurate. Answer is No, an C is clearly the best answer