The initial population of a town is 3000​, and it grows with a doubling time of 10 years. What will the population be in 8 ​years?

Answer 1

This is an example of exponential growth. The growth law for this problem is

P(t) = 3000 (2)^t/10,

where t is the number of years elapsed. To get the population after 8 years, plug t=8 into the equation and evaluate.