Arturo O. answered 05/05/20
Experienced Physics Teacher for Physics Tutoring
h(t) = -16t2 + 128t + 4
(a)
The initial height is 4 ft.
(b)
Maximum height is at the vertex of the height-vs.-time parabola, which is at
t = -b/(2a) = -128/[2(-16)] sec = ? sec
(c)
Evaluate h(t) at the time found in part (b) to get the maximum height.