Jessie S.
asked • 05/04/20Complete the recursive formula of f(n).
f(n) =-11+22(n-1)
f(1) =
f(n) =f(n-1) +
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2 Answers By Expert Tutors
Arthur D. answered • 05/04/20
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f(n)=f(n-1)+ ?
-11+22(n-1)=-11+22(n-1-1)+ ?
-11+22(n-1)=-11+22(n-1)+(-22)+ ?
?=22
Shrabana G. answered • 05/04/20
Tutor
New to Wyzant
Math tutor with Software Engg background
f(1) = -11 +22 (1-1) = -11
f (2) = -11 +22(2-1) = -11 +22 = 11
f(3) = -11 +22 (3-1) = -11 +22*2 = -11 +44 = 33
the common difference is 22
so f(n) = f(n-1 ) +22
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Paul M.
05/04/20