Arthur D. answered 05/04/20
Forty Year Educator: Classroom, Summer School, Substitute, Tutor
sect=5
sect=1/cost
1/cost=5
cost=1/5
sin(t/2)+cost=√((1-cost)/2)+cost=
√((1-0.2)/2)+0.2=
√(0.8/2)+0.2=
√(0.4)+0.2=
√(4/10)+0.2=
√(4/10)+(1/5)=
2/√10+(1/5)=
2√10/10 + (1/5)=
2√10/10 + (2/10)=
(2√10+2)/10=
(√10+1)/5