Emily R. answered 05/03/20
Qualified ELA/Math Teacher
To solve this problem, we must break it down into pieces to begin:
First lets look at what the problem tells us:
- Total students = 155
- Total buses = 5
- Total seats in row = 4
- Total rows needed = ? or X
Now lets determine what type of problem this will be. Typically, we look for key words to determine if it is going to be subtraction, addition, multiplication, or division. Since there are no keys words, we may have to examine the problem. Since we are dividing students into buses, I assume it will be a division problem. So now lets return to our data.
Lets fill in what we know =
- total students = number of buses * seats in a row * rows on a bus
- 155 = 5 * 4 * x
Now we need to solve the equation
- 155 = 5 * 4 * x (multiply 5*4)
- 155 = 20x (divide each side by x)
- 7.75 = X
Since we cannot have .75 of a row, we have to round UP to the nearest whole number. If we rounded down, then there wouldn't be enough seats for kids. There will be extra seats, but that is okay.
We need 8 rows on each bus.
To check our math, we go back to our original equation:
- total students = number of buses * seats in a row * rows on a bus
- 155 = 5 * 4 * 8
- 155 = 200 -- This is correct since there are now enough seats for all of the kids on the trip.
If we're still not sure, we can try the same problem with 7 rows.
- total students = number of buses * seats in a row * rows on a bus
- 155 = 5 * 4 * 7
- 155 = 140 - If there are 7 rows, there are 15 kids who won't have seats.
Therefore, the answer to this question is 8 rows per bus to fit all 155 kids on the 5 buses going on the field trip.