3(2d-1)-2d=4(d-2)+5

Answer 1

I assume you want a solution for d.

3(2d - 1) - 2d = 4(d - 2) + 5

6d - 3 - 2d = 4d - 8 + 5

4d - 3 = 4d - 3

-3 = -3

You are left with something that is always true, regardless of d. The quantity d cancelled out.