David S.

asked • 05/02/20

Help with math, please anyone

Find the range of the function f of x equals the integral from 0 to x of the square root of the quantity 16 minus t squared.

Options:

1)  [-4, 4]

2)  [0, 4]

3)  [0, 4π]

4)  [0, 8π]


1 Expert Answer

By:

Bob B. answered • 05/02/20

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Hi David S.


The answer is (a) [-4,4]. The key to figuring this problem out is to look at the argument in the square root

16-t2. For the integrand to remain real valued, t has to range between -4 and 4. Accordingly, so does x.

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