
Mark M. answered 05/01/20
Tutor
5.0
(278)
Mathematics Teacher - NCLB Highly Qualified
Asector = (θ / 2)(r2)
45π / 4 = (9π / 20)(r2)
225π = 9π (r2)
225π / 9 = πr2
225π / 9 = Acircle
Mark M. answered 05/01/20
Mathematics Teacher - NCLB Highly Qualified
Asector = (θ / 2)(r2)
45π / 4 = (9π / 20)(r2)
225π = 9π (r2)
225π / 9 = πr2
225π / 9 = Acircle
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