name the point afterneach of these translations. T(3,-2)(5,3), ry=x(-1,4), ry=0(3,-5), R(0,0)90 degrees(1,2), R(3,-4)90 degrees(2,3)

Answer 1

I hope this answer still finds you in time...

T (3, -2) ----> (5, 3): I don't understand this one. Are you translating along the vector <5, 3>?

R_y=x (-1, 4). A reflection in the line y=x has the rule (x, y)---> (y, x). Just flip the coordinates: (4, -1)

R_y=0: A reflection in the line y=0 is a reflection across the x-axis. (y=0 is the x-axis!) . So, a reflection about the x-axis has the rule: (x, y)--->(x, -y). Your coordinate is (3, -5), so all you have to do is negate the y-coordinate: (3, 5).

R₉₀ for (0, 0), (1, 2), (3, -4), (2, 3): I am assuming this is a "counterclockwise rotation" because you did not specify. Usually this is the default for rotation problems. The 90 CCW rotation rule is: (x, y)---> (-y, x):

(0, 0), (-2, 1), (4, 3), (-3, 2).

Answer 2

T(3,-2)(5,3) translate point (3,-2) five points to the right and 3 points up: (8,1)

ry=x(-1,4) reflect point (-1,4) across line y=x: (4,-1)  

R(0,0)90 degrees(1,2)   rotate the origin 90 degrees from quadrant 1 to 2:    (0,0)



R(3,-4)90 degrees(2,3)   rotate point (3,-4) 90 degrees from quadrant 2 to 3:     (-4,-3)