What is the missing constant term in the perfect square that starts with x2 + 6x ?

Answer 1

x² + 6x + c

To find "c" take the number in front of the "x", which in this case is 6, and divide it by 2, then square it, So, in this case 6/2 = 3 and 3² = 9, so c = 9

Answer 2

(x+3)² = x² + 6x + 9