The difference of the square of a number and 4 is equal to 3 times that number. Find the negative solution.

Answer 1

Let the number be 'a':

The difference of the square of a number and 4

a^2 -4

is equal to 3 times that number.

= 3*a

a^2 -4 =3a

a^2 -3a -4=0

(a-4) (a+1)=0

solutions are: 4 and -1

Answer 2

x² - 4 = 3x

x² - 3x - 4 = 0

(x - 4)(x + 1) = 0

Can you finish from here?