complete the equation of the line through (6, -6) and (8, 8)

Question

I just need to know what y equals.

Answer 1

Complete the equation of the line through (6, -6) and (8, 8)

Find the slope (m):  

m = (y2-y1) / (x2 - x1).  

 m = 8-(-6) / (8 - 6)

        m = 14 / 2 

 m= 7

Set up the equation in standard form, using either of the 2 given points. Let’s use (8, 8):

y-y1 = m(x-x1)

y-8 = 7(x-8)

Finally, solve for “y”

y-8 = 7(x-8)

y-8 = 7x-56

y = 7x - 56 + 8

y = 7x - 48

Answer 2

Hi there! You're looking for the formula y = mx + b where m is the slope of the line and b is the y-intercept.

We have our two points (6, -6) and (8, 8). Remember that each point is written as a coordinate (x, y).

We can solve for the slope by using the equation m = (y2-y1)/(x2-x1) where y1 is -6 and y2 is 8; x1 is 6 and x2 is 8.

So now we have, m = (8- -6)/(8-6), when simplified is 14/2 or 7.

Now that m is 7, we can use our line equation to find b by plugging in either of our points.

Let's use (6, -6) in y = 7x + b ===> -6 = 7*6 + b ===> -6 = 42 + b ===> b = -48

Now that we have b, we can put it all together in our line equation.

Our line equation is: y = 7x - 48

Hope that helps!

Answer 3

Slope m = (8 - (- 6))/(8 - 6) = 14/2 = 7;

then equation of line: y - 8 = 7(x - 8); y = 7x - 48

Answer: y = 7x - 48